Ex 55, 7 Chapter 5 Class 12 Continuity and Differentiability (Term 1) Last updated at by Teachoo Introducing your new favourite teacher Teachoo Black, at only ₹ per month Join Teachoo Black Next Ex 55, 8 → Chapter 5 Class 12 Transcript Ex 96, 7 For each of the differential equation given in Exercises 1 to 12, find the general solution 𝑥𝑙𝑜𝑔𝑥 𝑑𝑦/𝑑𝑥𝑦=2/𝑥 𝑙𝑜𝑔𝑥 Step 1 Put in form 𝑑𝑦/𝑑𝑥 Py = Q xlog x 𝑑𝑦/𝑑𝑥 y = 2/𝑥 log x Dividing by x log x, 𝑑𝑦/𝑑𝑥𝑦" × " 1/ (𝑥 log𝑥 If xy = e^(x y), then prove that dy/dx = (log x)/(1 log x)^2 asked in Mathematics by Samantha (391k points) continuity and differntiability;
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If log(x y/2)=1/2(logx logy) then find the value of x/y y/x-Log (xy/7)= 1/2 (logx log y) Multiplying both sides by 2 we get 2Log (xy/7)= (logx log y) here logx log y can be written as log (x*y) Taking antilog in both sides, we get (xy/7)^2 = xy OnAlgebra Solve for x log of x=2 log(x) = 2 log ( x) = 2 Rewrite log(x) = 2 log ( x) = 2 in exponential form using the definition of a logarithm If x x and b b are positive real numbers and b b ≠ ≠ 1 1,



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Antilogarithm calculator In order to calculate log 1 (y) on the calculator, enter the base b (10 is the default value, enter e for e constant), enter the logarithm value y and press the = orAnswer (1 of 7) For solving this type of questions you should know some basic operations of logarithms Now for this question we can write log x / log y = log (xy) and log( xy ) = logxIf logx y = 100 and log2 x = 10, then the value of y is a) 2 10 b) 2 100 c) 2 1000 d) 2 If logx y = 100 and log2 x = 10, then the value of y is a) 2 10 b) 2 100 c) 2 1000 d) 2 Login
Click here👆to get an answer to your question ️ If log (x^2 y^2) = 2 tan^1 (yx) then dydx = Solve Study Textbooks Guides Join / Login >> Class 12 >> Maths >> Continuity and Differentiability >> log ( x y )/3 = 1/2 ( logx logy) 2× log ( x y )/3 = log x log y log ( x y ) / 3 ^2 = log xy { since i ) n log a = log a^n ii ) log a log b = log ab } Remove log bothsides, (X d 2 y/dx 2 = a 2 / (abx) 2 Multiply both sides by x 2 x 3 d 2 y/dx 2 = a 2 x 2 / (abx) 2 (ii) Squaring both sides (i) (x dy/dx – y) 2 = a 2 x 2 / (abx) 2 = x 3 d 2 y/dx 2 from (ii) So x 3 d 2
Log { {xy}/3}=1/2 {logxlog Y} log (xy) log (3) = 1/2 (log xy) log (xy) log (2) = 1/2 (log xy) 2xy 4 = xy xy = 4 now x/y y/x = (x^2 y^2) / xy = (x^2 y^2) / 4S=log (y) So, e^t=x and e^s=y hence, xy= (e^s)* (e^t) So, xy=e^ (ts) On applying log log (xy)= ts= logxlogy Philip Lloyd Specialist Calculus Teacher, Motivator and Baroque Trumpet If u = log(x2 y2)/xy then x(∂u/∂x) y(∂u/∂y) is (a) 0 (b) u (c) 2u (d) u – 1 Login Remember Register;



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1 2 y = 2 2 x ⇒ y = 2 x, if we plug this into first equation we have y 2 = y ⇒ y 2 − y = 0 ⇒ y ( y − 1) = 0 ,so y 1 = 0 and y 2 = 1 which means that x 1 = 0 and x 2 = 1 2 Since l n isn't defined for 0 onlyقم بحل مشاكلك الرياضية باستخدام حلّال الرياضيات المجاني خاصتنا مع حلول مُفصلة خطوة بخطوة يدعم حلّال الرياضيات خاصتنا الرياضيات الأساسية ومرحلة ما قبل الجبر والجبر وحساب المثلثات وحساب التفاضل والتكامل والمزيدIf log `((xy)/3)=1/2 (log x log y)` then find the value of `x/yy/x` log ( xy /3)=1/2 (log x log y) అయిన x/y y/x విలువలను కనుగొనండి



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y = log(x2) ⇒ dy dx = 1 x2 d dx (x2) = 1 x2 ×2x = 2 x Approach 2 Using the law of logs then differentiate Reminder ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯∣∣ ∣ 2 2logxn = nlogx2 2 ∣∣ ∣Click here👆to get an answer to your question ️ If log x log y log z = (y z)(z x)(x y) , then which of the following condition is true?Let y = (log x) x x log x Also, let u = (log x) x and v = x log x ∴ y = u v dy dx du dx dv dx ⇒ dy dx = du dx dv dx (1) u = (logx) x ⇒ log u = log (log x) x ⇒ log u = x log (log x)



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If #logx/(a^2abb^2)=log y/(b^2bcc^2)=log z/(c^2caa^2)# then find #x^(ab)* y^(bc)*z^(ca)=#?Solution for 2 x log x y = logx dxVyriešte matematické problémy pomocou nášho bezplatného matematického nástroja, ktorý vás prevedie jednotlivými krokmi riešení Podporované sú základné matematické funkcie, základná aj



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This process reflects the equation about \displaystyle{y}={x} \displaystyle{y}={10}^{{{{\log}_{{10}}{\left({2}\right)}}{\left({x}{2}\right)}}} Explanation UsingGraph y = log of x2 y = log(x 2) y = log ( x 2) Find the asymptotes Tap for more steps Set the argument of the logarithm equal to zero x 2 = 0 x 2 = 0 Subtract 2 2 from both sides ofCorrect option is A) We have log yxlog xy=2,x 2y=12 If log yx=a , then log xy= a1,∵log ab= log ba1 ⇒a a1=2 ⇒a 21=2a ⇒(a−1) 2=0 ⇒a=1 Hence, y=x Substituting in the equation, we get



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Ch 1 Real Numbers, Exercise 156 If log(xy)/3 = 1/2 (logxlogy),find the value of x/yy/x AP SCERT Mathematics Textbook, Pg 23CCE MODEL, AP/TG Class 10Solve for x log of x=y log(x) = y log ( x) = y Rewrite log(x) = y log ( x) = y in exponential form using the definition of a logarithm If x x and b b are positive real numbers and b b ≠ ≠ 1 1, then151 5=0 are conjugate lines with respect to the circle 12 Find the value of k if kx 3y1=0, 2x



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The logarithm log b (x) = y is read as log base b of x is equals to y Please note that the base of log number b must be greater than 0 and must not be equal to 1 And the number (x) which weLet us simplify log(x−y)/2=1/2(logx×y) log(x−y)/2=1/2logxy log(x−y)/2=log(xy) 1/2 By cross multiplying, we get (x−y) 2=4xy x 2y 2−2xy=4xy x 2y 2=4xy2xy x 2y 2=6xyCh 1 Real Numbers, Exercise 155 If x^2 y^2 = 25xy, then prove that 2log(xy) = 3log3 log xlogyAP SCERT Mathematics Textbook, Pg 23CCE MODEL, AP/TG Cl



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x/y =1/2(3 sqrt(5)) From 2 log(xy)=log x log y we know (xy)^2=xy Now calling x = lambda y and substituting (lambda yy)^2=lambda y^2 or supposing y > 0 (lambdaCompute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history if log x y 2 1 2 logx logy logz then find the value of x y y x Mathematics TopperLearningcom 9g3iizyy if log x y 2 1 2 logx logy logz then find the value of x y y x



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Log y = log (x(log x)^(log (log x)) = (log x)log log x log x log (log y) = log (log x)log log x(log x) (1 / log y) (1 / y) (dy / dx) = 2 log (log x) (1 / log x) (1 / x) (1 / log x) (1 / x) (1 / y log y) (dy Prove #x^(log_10(y)log_10(z))y^(log_10(z)log_10(x))z^(log_10(x)log_10(y))=1# Use the base 10 logarithm on both sides #log_10(x^(log_10(y)log_10(z))y^(log_10(zWhen the argument of a logarithm is a fraction, the logarithm can be rewritten as the subtraction of the logarithm of the numerator minus the logarithm of the denominator log b (x / y) = log b



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